Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 2 Lesson 23 Answer Key

Eureka Math Grade 5 Module 2 Lesson 23 Problem Set Answer Key

Question 1.
Divide. Then, check using multiplication.

a. 4,859 ÷ 23

Answer:
4859/23 = 6.

Explanation:
In the above-given question,
given that,
Divide, and then check.
23 x 2 = 46.
48 – 46 = 2.
23 x 1 = 23.
29-23 = 6.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (1)

b. 4,368 ÷ 52

Answer:
4368/52 = 0.

Explanation:
In the above-given question,
given that,
Divide, and then check.
52 x 8 = 416.
436 – 416 = 20.
52 x 4 = 208.
208-208 = 0.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (2)

c. 7,242 ÷ 34

Answer:
7242/34 = 0.

Explanation:
In the above-given question,
given that,
Divide, and then check.
34 x 2 = 68.
72 – 68 = 4.
34 x 1 = 34.
102-102 = 0.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (3)

d. 3,164 ÷ 45

Answer:
3164/45 = 5.

Explanation:
In the above-given question,
given that,
Divide, and then check.
45 x 7 = 315.
316 – 315 = 1.
45 x 3 = 140.
140-135 = 5.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (4)

e. 9,152 ÷ 29

Answer:
9152/29 = 17.

Explanation:
In the above-given question,
given that,
Divide, and then check.
29 x 2 = 87.
91 – 87 = 4.
29 x 5 = 145.
162-145 = 17.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (5)

f. 4,424 ÷ 63

Answer:
4424/63 = 22.

Explanation:
In the above-given question,
given that,
Divide, and then check.
63 x 5 = 315.
442 – 315 = 27.
63 x 4 = 279.
279-252 = 22.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (6)

Question 2.
Mr. Riley baked 1,692 chocolate cookies. He sold them in boxes of 36 cookies each. How much money did he collect if he sold them all at $8 per box?

Answer:
The money did she collect = $5.9.

Explanation:
In the above-given question,
given that,
Mr. Riley baked 1692 chocolate cookies.
he sold them in boxes of 36 cookies each.
36x 8 = 288.
1692/288.
5.9$.

Question 3.
1,092 flowers are arranged into 26 vases, with the same number of flowers in each vase. How many flowers would be needed to fill 130 such vases?

Answer:
The number of flowers needed to fill 130 such vases = 8 flowers.

Explanation:
In the above-given question,
given that,
1092 flowers are arranged into 26 vases,
with the same number of flowers in each vase.
1092/26 = 42.
1092/130 = 8.4.

Question 4.
The elephant’s water tank holds 2,560 gallons of water. After two weeks, the zookeeper measures and finds that the tank has 1,944 gallons of water left. If the elephant drinks the same amount of water each day, how many days will a full tank of water last?

Answer:
The number of days will a full tank of water last = 4.15 gallons.

Explanation:
In the above-given question,
given that,
The elephant’s water tank holds 2560 gallons of water.
after two weeks, the zookeeper measures and finds that the tank has 1944 gallons of water left.
if the elephant drinks the same amount of water each day.
2560 – 1944.
616.
2560/616.
4.15 gallons.

Eureka Math Grade 5 Module 2 Lesson 23 Exit Ticket Answer Key

Divide. Then, check using multiplication.
a. 8,283 ÷ 19

Answer:
8283/41 = 1.

Explanation:
In the above-given question,
given that,
Divide, and then check.
41 x 2 = 82.
82 – 82 = 0.
41 x 2 = 82.
83-82 = 1.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (7)

b. 1,056 ÷ 37

Answer:
1056/37 = 20.

Explanation:
In the above-given question,
given that,
Divide, and then check.
37 x 2 = 74.
105 – 74 =31.
37 x 8 = 296.
316-296 = 20.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (8)

Eureka Math Grade 5 Module 2 Lesson 23 Homework Answer Key

Question 1.
Divide. Then, check using multiplication.
a. 9,962 ÷ 41

Answer:
9962/41 = 40.

Explanation:
In the above-given question,
given that,
Divide, and then check.
41 x 2 = 82.
99 – 82 = 17.
41 x 2 = 122.
122-82 = 40.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (9)

b. 1,495 ÷ 45

Answer:
1495/45 = 10.

Explanation:
In the above-given question,
given that,
Divide, and then check.
45 x 3 = 135.
149 – 135 = 14.
45 x 3 = 135.
145-135 = 10.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (10)

c. 6,691 ÷ 28

Answer:
6691/28 = 27.

Explanation:
In the above-given question,
given that,
Divide, and then check.
28 x 2 = 56.
66 – 56 = 10.
23 x 8 = 251.
251-224 = 27.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (11)

d. 2,625 ÷ 32

Answer:
2625/32 = 33.

Explanation:
In the above-given question,
given that,
Divide, and then check.
32 x 8 = 256.
262 – 256 = 6.
32 x 1 = 32.
65-32 = 33.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (12)

e. 2,409 ÷ 19

Answer:
2409/19 = 15.

Explanation:
In the above-given question,
given that,
Divide, and then check.
19 x 1 = 19.
24 – 19 = 5.
19 x 6 = 126.
126-114 = 15.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (13)

f. 5,821 ÷ 62

Answer:
5821/62 = 55.

Explanation:
In the above-given question,
given that,
Divide, and then check.
62 x 9 = 558.
582 – 558 = 24.
62 x 3 = 241.
241-186 = 55.
Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (14)

Question 2.
A political gathering in South America was attended by 7,910 people. Each of South America’s 14 countries was equally represented. How many representatives attended from each country?

Answer:
The representatives attend from each country = 565.

Explanation:
In the above-given question,
given that,
A political gathering in south America was attended by 7910 people.
each of south America’s 14 countries was equally represented.
7910/14 = 565.

Question 3.
A candy company packages caramel into containers that hold 32 fluid ounces. In the last batch, 1,848 fluid ounces of caramel were made. How many containers were needed for this batch?

Answer:
The containers were needed for this batch = 58 containers.

Explanation:
In the above-given question,
given that,
A candy company packages caramel into containers that hold 32 fluid ounces.
In the last batch, 1,848 fluid ounces of caramel were made.
1848/32.
57.75.
58.

Eureka Math Grade 5 Module 2 Lesson 23 Answer Key (2024)
Top Articles
Latest Posts
Article information

Author: Horacio Brakus JD

Last Updated:

Views: 6327

Rating: 4 / 5 (71 voted)

Reviews: 86% of readers found this page helpful

Author information

Name: Horacio Brakus JD

Birthday: 1999-08-21

Address: Apt. 524 43384 Minnie Prairie, South Edda, MA 62804

Phone: +5931039998219

Job: Sales Strategist

Hobby: Sculling, Kitesurfing, Orienteering, Painting, Computer programming, Creative writing, Scuba diving

Introduction: My name is Horacio Brakus JD, I am a lively, splendid, jolly, vivacious, vast, cheerful, agreeable person who loves writing and wants to share my knowledge and understanding with you.